How many moles of NH4NO3 are obtained when four moles of zinc are completely consumed by excess of very dilute HNO3?
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Answer:
+5 to −3 is answer
Generally, when zinc reacts with nitric acid, it forms zinc nitrate. But when we take very dilute solution of nitric acid, if forms ammonium nitrate as well.
So, here Nitrogen is reducing from +5 to −3.
4Zn(s)+
10HNO
3
+5
(aq)⟶4Zn(NO
3
)
2
(aq)+
N
−3
H
4
NO
3
(aq)+3H
2
O(l)
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Answer:
How many moles of NH4NO3 are obtained when four moles of zinc are completely consumed by excess of very dilute HNO3?
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