How many moles of nitrate ions are there in 66.2g of lead nitrate?
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Pb(NO3)2... Mol.mass = 207 + 28 + 96
= 324g/mole.
Mass/mol.mass = 66.2g/324g/mole = 0.204 moles of Nitrate ions.
= 324g/mole.
Mass/mol.mass = 66.2g/324g/mole = 0.204 moles of Nitrate ions.
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