Question

HOW MANY MOLES OF NITROGEN ARE NEEDED TO PRODUCE 8.2 MOLE OF AMMONIA BY THE REACTION WITH HYDROGEN?

Answer 1

Here is how you crack it up;

write a balanced chemical equation for the reaction

N + H ⇄ NH3

since these elements exist as diatomic gases,

∴N2 + H2 ⇄ NH3

now to balance it, make sure the number of atoms on both sides of the equation are equal, thus;

N2 + 3H2 ⇄ 2NH3. Now to compare the mole ratios

there is 1mol of N2 which reacted with 3mol of H2 to produce 2mol of NH3

we say, 1mol(N2) : 2mol(NH3)

              Xmol     :  8.2mol ,                  and to do the calculation,

2X = 8.2,

     = 4.1mol of N2

Hence, 4.1mol of N2 were needed to produce 8.2moles of NH3

Answer 2

Answer:

Explanation:

Here is how you crack it up;

write a balanced chemical equation for the reaction

N + H ⇄ NH3

since these elements exist as diatomic gases,

∴N2 + H2 ⇄ NH3

now to balance it, make sure the number of atoms on both sides of the equation are equal, thus;

N2 + 3H2 ⇄ 2NH3. Now to compare the mole ratios

there is 1mol of N2 which reacted with 3mol of H2 to produce 2mol of NH3

we say, 1mol(N2) : 2mol(NH3)

             Xmol     :  8.2mol ,                  and to do the calculation,

2X = 8.2,

    = 4.1mol of N2

Hence, 4.1mol of N2 were needed to produce 8.2moles of NH3