Question

How many moles of nitrogen atoms are combined with 8.6 moles of oxygen atoms in n2o5?

Answer 1

Therefore 1 mole of oxygen gas contains 2 moles of oxygen atoms. And 0.4 moles of oxygen gas contains 0.8 moles of oxygen atoms.

Answer 2

Answer:

3.44 moles of nitrogen atoms are required to combine with 8.60 moles of oxygen atoms.

Explanation:

An atom is a particle of matter that exceptionally characterizes a chemical component. An atom comprises a focal core encircled by at least one adversely charged electron. The core is emphatically charged and contains at least one somewhat weighty particle known as protons and neutrons.

Dinitrogen Pentoxide is, $N_{2} O_{5}$ which means that there are 2 Nitrogen atoms for every 5 Oxygen atoms.

$2N_{2} +5O_{2}$  ⇒  $2N_{2} O5$

2 moles of $N_{2}$ ⇒ 5 moles of $O_{2}$

Hence, 1 mole of oxygen will require 2/5 moles of nitrogen.

1 mole of $O_{2}$  ⇒  $\frac{2}{5}$ moles of $N_{2}$

Now, we have 8.60 moles of oxygen atoms, therefore required moles of nitrogen atoms is

8.60  moles of $O_{2}$  ⇒ $\frac{8.6*2}{5}$ moles of $N_{2}$

⇒ 3.44 moles    

∴ 3.44 moles of nitrogen atoms are required to combine with 8.60 moles of oxygen atoms.

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