Question

How many moles of nitrogen atoms are combined with 8.60 mol of oxygen atoms is dinitrogen pentoxide, N2O5​

Answer 1

Answer:

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Answer 2

3.44 moles of nitrogen atoms are combined with 8.60 moles of oxygen atoms in dinitrogen pentoxide, N2O5.

• The formula of Dinitrogen Pentoxide is, $N_{2}O_{5}$  which means that there are 2 Nitrogen atoms for every 5 Oxygen atoms.
• Hence, 1 mole of oxygen will require 2/5 moles of nitrogen.
• We have 8.60 moles of oxygen atoms, therefore moles of nitrogen required will be:

                   $\frac{8.60*2}{5} = 3.44$

• Therefore, in Dinitrogen Pentaoxide, $N_{2}O_{5}$  3.44 moles of nitrogen atoms are combined with 8.60 moles of oxygen atoms.