How many moles of nitrogen atoms are in 52.5g of nitrogen gas?
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Solution
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P=
76
74.2
atm
V=?
m=5.25g
M=28g
T=273+26=299K
PV=nRT
76
74.2
×V=
M
m
×0.0821×299
V=
28
5.25
×0.0821×299×
74.2
76
V=4.7107L
Explanation:
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