Question

how many moles of O2 are present in 10.6g of NaCo3

Answer 1

Moles of NaCO3=10.6÷83=approx 0.128 Since 1 mole of given molecule have 3 mole oxygen atom hence 0.128 mole have 3×0.128 =0.384 moles of O atom Hence moles of O2=0.384÷2=0.192 moles