Question

how many moles of O2 are produced when 6.0 mol of KCIO3 decompose completely

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Answer 1

Explanation:

Complete step-by-step solution:We are given to find the no. of moles of O2 produced from decomposition of 6.0 mole of KClO3.

Potassium chlorate KClO3 is strongly heated to break it down into

n ionic potassium compound called potassium chloride releasing oxygen gas.

The reaction of the above process is 2KClO3→heat2KCl+3O2↑

As we can see 2 moles of potassium chlorate gives 2 moles of potassium chloride and 3 moles of oxygen gas.

As when 6 moles of potassium chlorate is heated it gives m moles of potassium chloride and n moles of oxygen gas.

The value of m will be equal to 6.0 as the no. of moles of potassium chlorate and potassium chloride is equal.

The value of n will be

2moles of KClO3------>3moles of O2

6moles of KClO3------>n moles of O2

6/2=n/3

n=3x6/2=9

Therefore, 6.0 mole of KClO3 gives 9.0 moles of O2 gas.

Answer 2

Answer:

Explanation:

Complete step-by-step solution:We are given to find the no. of moles of O2 produced from decomposition of 6.0 mole of KClO3.

Potassium chlorate KClO3 is strongly heated to break it down into

n ionic potassium compound called potassium chloride releasing oxygen gas.

The reaction of the above process is 2KClO3→heat2KCl+3O2↑

As we can see 2 moles of potassium chlorate gives 2 moles of potassium chloride and 3 moles of oxygen gas.

As when 6 moles of potassium chlorate is heated it gives m moles of potassium chloride and n moles of oxygen gas.

The value of m will be equal to 6.0 as the no. of moles of potassium chlorate and potassium chloride is equal.

The value of n will be

2moles of KClO3------>3moles of O2

6moles of KClO3------>n moles of O2

6/2=n/3

n=3x6/2=9

Therefore, 6.0 mole of KClO3 gives 9.0 moles of O2 gas.

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Explanation: