Question

How many moles of of KOH are needed to exactly neutralize 500. mL of 1.0 M HCl?

Answer 1

Answer : The number of moles of KOH needed to neutralize are, 0.5 mole

Explanation : Given,

Concentration of HCl = 1.0 M

Volume = 500 ml = 0.5 L

First we have to calculate the moles of HCl.

$\text{Moles of }HCl=\text{Concentration of }HCl\times \text{Volume}=1.0mole/L\times 0.5L=0.5mole$

The moles of HCl = 0.5 mole

Now we have to calculate the moles of KOH.

The balanced chemical reaction will be,

$HCl+KOH\rightarrow KCl+H_2O$

From the balanced chemical reaction, we conclude that the ratio of HCl and KOH is, 1 : 1

That means,

The number of moles of HCl = The number of moles of KOH = 0.5 mole

Therefore, the number of moles of KOH needed to neutralize are, 0.5 mole