Question

how many moles of oxygen are given by the complete composition of 1.225 g kclo3​

Answer 1

Answer:

6.022into 10*23 .....1.225gkclo3 molecules

Answer 2

Explanation:

A balanced equation for this is:

2KClO3 ————- 2KCl + 3O2

So the answer is 3 moles of O2 is given

But if we want to go further to calculate the mass of O2 given,

Molar mass of KClO3 = 39 + 35.5 + 3 (16) = 122.5

Molar mass of O2 = 32

2 moles of KClO3 ———— 3 moles of O2

2(122.5) of KClO3 ———— 3(32) of O2

245g of KClO3 ————— 96g of O2

Thus 1.225g of KClO3 ————— x (unknown)

x = 1.225 * 96 ÷ 245 = 0.48g

Thus 0.48g of O2 is given