Question

how many moles of oxygen are obtained by heating 8 mol of potassium chlorate​

Answer 1

The equation is:-

K C l O 3 →  2KC l + 3 O 2

=> 8 = 3 * 8/3

=> 2:3 = 2  × 8 /3  :  3  ×  8/ 3  =  2  ×  8/ 3  :  8

=> Therefore, to produce  8  moles of Potassium chlorate,  2  ×  8/ 3  =  5.33  moles of Oxygen is needed.

Hope it helps you :)

Answer 2

Given: The given quantity is 8 mol of potassium chlorate.

To find: We have to find out the moles of oxygen are obtained by heating 8 mol of potassium chlorate.

Solution:

The chemical formula of potassium chlorate is $KClO_3$.

When potassium chlorate is heated potassium chloride (KCl) along with oxygen is obtained.

The reaction is -

$2KClO_3\rightarrow 2KCl+3O_2$

So, 2 moles of potassium chlorate reacts to form 3 moles of oxygen along with 2 moles of potassium chloride.

Thus 8 mole of potassium chlorate reacts to form

$\dfrac{8\times 3}{2}=12$ moles of oxygen.

12 moles of oxygen will obtain by heating 8 mol of potassium chlorate.