How many moles of oxygen are present in 0.45kg of fe2o3
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Answer: 2.8 moles of Oxygen.
Explanation:
Molar mass of Fe2O3
Fe2=56*2=112g/mol
O3=16*3=48
Therefore,
112+48=160g/mol
Number of moles of Oxygen present =Mass of Fe2O3 given / Molar mass of Fe2O3
But we are working in gram.
Therefore 0.45kg=450g
Number of moles of oxygen = 450/160
=2.8moles of oxygen.
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