Question

How many moles of oxygen are present in 450 g of Fe2O3?

Answer 1

Answer:

No. of moles = Mass / Molar Mass

Mass = 450 gm

Molar Mass of Fe2O3 = 56 × 2 + 16× 3

= 112 + 48 = 160 gm

No. of Moles = 450 / 160

= 2.8

Hence 2.8 moles of oxygen are present in 450 g of Fe2O3.

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