How many moles of oxygen are required to react with 65.3 g of Aluminium in the production of aluminium oxide?
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Answer:
The answer is 1.81 Moles (approx)
Explanation:
4Al+3O2 gives 2Al2O3
Moles of Al=given mass/molar mass
=65.3/27
=2.41
Now, 4 Moles of Al reacts with 3 Moles of O2
1 mole of Al reacts with 3/4 mole of O2
2.41 Moles of Al reacts with 3/4*2.41=1.81(approx)
Hope it will help..
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