Question

How many moles of oxygen atoms are present in 0.3 moles of H2S2O7

Answer 1

Explanation:

of atoms in 0.3 mole of ozone. = 3 × 1.81 × 10^23 atoms. Now, 3 × 1.81 × 10^23 atoms of oxygen are present in 0.3 moles of Ozone.

Answer 2

Answer:

2.1 moles of oxygen atoms are present in $H_{2}S_{2}O_{7}$.

Explanation:

We know that in one molecule of $H_{2}S_{2}O_{7}$seven oxygen atoms, two sulphur atoms and two hydrogen atoms are present.

In one mole of $H_{2}S_{2}O_{7}$seven moles of oxygen atoms, two moles of sulphur and two moles of hydrogen are present.

For 0.3 mole of $H_{2}S_{2}O_{7}$, we need to calculate the number of moles of oxygen atoms in it as follows-

$H_{2}S_{2}O_{7}$ → $O_{2}$

1          =      7

0.3      =      $x$

7 × 0.3 = 1 × $x$

2.1 = $x$

Conclusion:

There are 2.1 moles of oxygen atoms available in 0.3 moles of $H_{2}S_{2}O_{7}$.