How many moles of oxygen atoms are present in 0.350 moles of lead sulphate a component of lead acid batteries
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0.35 answer
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= 0.350 moles of PbSO4 * 4 moles of O2 / 1 moles PbSO4
=1.4 moles of O2 are presented in 0.350 mole of lead sulphate .
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