Question

How many moles of oxygen gas would be needed to react completely with 8 moles of lithium metal in the following reaction? 4Li + O2 → 2Li2O a 1 b 3 c 2 d 6

Answer 1

Answer:

The number of moles of oxygen that will react with 8 moles of lithium will be four.

Explanation:

The given equation is:

$4Li+O_{2}--->2Li_{2}O$

As per stoichiometry of equation, four moles of lithium will react with one mole of oxygen to give two moles of lithium oxide.

Thus the number of moles of oxygen that will react with one mole of lithium will be half.

$The moles of oxygen that will react with eightmoles of Li=8X\frac{1}{2}mol$

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Answer 2

2 moles of oxygen gas would be needed to react completely with 8 moles of lithium metal in the following reaction.

Explanation:

Balanced chemical reaction : It is defined as the reaction in which the number of atoms of individual elements present on reactant side must be equal to the product side.

The balanced chemical reaction is:

$4Li+O_2\rightarrow 2Li_2O$  

According to stoichiometry :

4 mole of lithium $(Li)$ require=  1 mole of $O_2$

Thus 8 moles of lithium $(Li)$  will require=$\frac{1}{4}\times 8=2moles$  of $O_2$

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