How many moles of P4 are needed to react with 9 moles of Mg? 6 Mg + P4 → 2 Mg3P2
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Let us look at the equation;
6Mg + P4 .............>2 Mg3 P2
according to this equation 1 mole of P4 reacts with 6 moles of Mg. So my recipe is 1 mole of P4is required for every 6 moles of Mg.
1 mole of P4 / 6 moles of Mg ......(a)
X moles of P4 completely reacts with 9 moles of Mg
X moles of P4 / 9 moles of Mg ......(b)
the two ratios are equal.
(a) = (b)
1 mole of P4 / 6 moles of Mg =
X moles of P4 / 9 moles of Mg
1 = X .6
6X = 9
X = 9/6 = 3/2 = 1.5 mole
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