Question

How many moles of p4 can be produced by reaction of0.10 moles of ca5(po4)3f, 0.36 moles sio2 and 0.90 moles c?

Answer 1

in this question let us find the limiting reagent first.

let us assume that Ca5(PO4)3F is consumed fully and the other 2 remains

so according to the balanced chemical equation,  4 moles of Ca5(PO4)3F will react with 18 moles of SiO2

so 0.1 moles react with 0.45 moles of SiO2, while the given amount is 0.36 moles.

So Ca5(PO4)3F cannot be the limiting reagent.

now let us go to SiO2 , here according to balanced chemical equation, 18 moles react with 4 moles of Ca5(PO4)3F.

so 0.36 moles of SiO2 will react with 0.08 moles which is less than the provided amount.

again 18 moles of SiO2 will react with 30 moles of C.

so 0.36 moles of SiO2 will react with 0.6 moles of C, which is also more than the provided amount.

so SiO2 is the limiting reagent.

now have to find the amount of product according to limiting reagent as the reaction will not carried forward after any reactant gets finished.

the the amount of any product produced can be found by balancing with the amount consumed of the limiting reagent.

so 18 moles of SiO2 will react to give 3 moles of P4

so 0.36 moles of will react to give 0.06 moles P4.

so 0.06 moles of P4 will be produced.(ans)

thanks

hope it helps !!!

Answer 2

Explanation:

0.06 is the answer. Hope it is helpful