How many moles of particles are formed by dissolving one mole of each of the following in water? CaCl2 mole(s) of particles
Answers
Answer:
for that entire slide
Explanation:
CaCl2 = 3
Sucrose= 1
Na2HPO4 = 3
Ethanol = 1
(NH4)2SO4 = 3
Given: the moles of CaCl₂, n = 1 mol
To Find: the number of particles, N.
Solution:
To calculate N, the formula used:
- Number of particles = number of moles x Avagardo's number (Nₐ)
- N' = n x Nₐ
Applying the above formula:
CaCl₂ on dissociation releases a total of 3 ions, one is a calcium ion and 2 chloride ions.
For Calcium ion -
Number of calcium ions, N₁ = n₁ x Nₐ
n, is the number of moles of Ca²⁺ ions i.e. n₁ = 1
Nₐ is 6.02 x 10 ²³ ions/molecules/atoms
∴ N₁ = 1 x 6.02 x 10 ²³
= 6.02 x 10 ²³calcium ions ⇒ 1
For chloride ions-
NUmber of chloride ions, N₂ = n₂ x Nₐ
here, the number of mol of for two chloride ions is 1 i.e. n₂= 2 x 1 = 2 mol
∴ N = 2 x 6.02 x 10 ²³
N₂ = 12.04 x 10 ²³ chloride ions ⇒ 2
Now total number of particles :
N = N₁ + N₂
On adding 1, and 2 -
N = 6.02 x 10 ²³+ 12.04 x 10 ²³
= 10 ²³( 6.02 + 12.04 )
= 18.06 x 10 ²³
N = 18.06 x 10 ²³particles