Question

How many moles of particles are formed by dissolving one mole of each of the following in water? CaCl2 mole(s) of particles

Answer 1

Answer:

for that entire slide

Explanation:

CaCl2 = 3

Sucrose= 1

Na2HPO4 = 3

Ethanol = 1

(NH4)2SO4 = 3

Answer 2

Given: the moles of CaCl₂, n = 1 mol

To Find: the number of particles, N.

Solution:

To calculate N, the formula used:

• Number of particles = number of moles x Avagardo's number (Nₐ)
• N'  =  n x Nₐ

Applying the above formula:

CaCl₂ on dissociation releases a total of 3 ions, one is a calcium ion and 2 chloride ions.

For Calcium ion -

Number of calcium ions, N₁ = n₁ x Nₐ

n, is the number of moles of Ca²⁺ ions i.e. n₁ = 1

Nₐ is 6.02 x 10 ²³ ions/molecules/atoms

∴ N₁ =  1 x 6.02 x 10 ²³

       = 6.02 x 10 ²³calcium ions                          ⇒ 1

For chloride ions-

NUmber of chloride ions, N₂ = n₂ x Nₐ

here, the number of mol of for two chloride ions is 1 i.e. n₂= 2 x 1 = 2 mol

∴ N = 2 x 6.02 x 10 ²³

   N₂ = 12.04 x 10 ²³ chloride ions                      ⇒ 2

Now total number of particles :

N = N₁ + N₂

On adding 1, and 2 -

N = 6.02 x 10 ²³+  12.04 x 10 ²³

   = 10 ²³( 6.02 + 12.04 )

   = 18.06 x 10 ²³

N = 18.06 x 10 ²³particles