Question

how many moles of Pb(NO3)2 are required to produce 48g of O2
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Answer 1

Answer: Amount of oxygen liberated should be equated to its equivalent number of moles of lead nitrate. Hence we can convert the amount of oxygen to number of moles. Hence 1.5 moles of oxygen = 2×1.5 = 3 moles of lead nitrate.

Answer 2

48g of O₂ has 1.5 moles

The decomposition of Pb(NO₃)₂ = 2Pb(NO₃)₂ =  2PbO+4NO₂+O₂

2 moles of Pb(NO₃)₂ give one mole of O₂

So, 3 moles of Pb(NO₃)₂ give 1.5 moles of O₂

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