how many moles of potassium chlorate is needed to produce 2.4 Mole of Oxygen
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Answer:
1.6 mol
Explanation:
2KClO3 --> 2KCl + 3O2
3 mole of oxygen is given by 2mole of KClO3
1 mole of oxygen= 2/3
2.4 mole of oxygen= 2/3×2.4
= 1.6 mol
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