Question

How many moles of potassium chlorate is to be heated to produce 11.2 litre oxygen?
(a) 1/2 mole
(b) 1/3 mole
(c) 1/4 mole
(d) 2/3 mole
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Answer 1

Answer:

How many moles of potassium chlorate is to be heated to produce 11.2 litre oxygen?

At NTP, 11.2 L of oxygen corresponds to $\frac{11.2}{22.4}$ = 0.5 mol.

2KC103 heat $\longrightarrow$ 2KC1 + 3O2

Thus, 2 moles of potassium chlorate on heating gives 3 moles of oxygen.

Thus, $\frac{2}{3}$ × 0.5 = $\frac{1}{3}$ moles of potassium chlorate on heating gives 11.2 L of oxygen at NTP.

Hence, the correct option is B

Answer 2

Answer:

☞(b) 1/3

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