Question

How many moles of potassium chlorate should
be decomposed completely to obtain 67.2 litres
of oxygen at STP ?​

Answer 1

Answer:

2Kclo3➡️2kcl +3o2

2moles kclo3=3*22.4ltrs

= 67.2ltrs

Therefore 67.2 ltrs = 2 mole of Kclo3

Given 67.2 ltrs =2 moles of Kclo3 (ans)