Question

How many moles of potassium chlorate sthe highest dipole moment is?

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Prakriti Deo asked in Chemistry

how many moles of potassium chlorate to be heated to produce 11 2 liters of oxygen

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Shubhangini Kumari answered this
6406 helpful votes in Chemistry, Class XII-Science

Dear student!

The production of oxygen from per chlorate is as follows:

2KClO3 (s) -> 2KCl (s) + 3O2(g)

so,  here 2 moles of per chlorate is used to produce 3 moles of oxygen gas.

So,  1 mole of oxygen gas will need = 2/3 moles of per chlorate.

Now we know that 1 mole of oxygen gas at STP = 22.4 L

So, 112 L oxygen gas = 112/22.4 =5 Moles of oxygen gas.

So, 5 moles (112L) of oxygen gas will be produced by = 5 x 2/3 moles of per chlorate = 3.33 moles

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