How many moles of silver chloride are produced from 15.0 mol of silver nitrate?
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Silver chloride is formed by the following reaction
Ag(NO₃) + NaCl -------> NaNO₃ + AgCl
Here, for 1 mole of Silver Nitrate, 143 grams of Silver chloride is formed. So for 15 moles of Silver nitrate, (15*143)= 2145 grams of Silver chloride is formed (By integral method)
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