Question

how many moles of sodium bicarbonate are needed to neutralise 0.8ml of sulpfuric acid atstp

Answer 1

Answer:

ideal gas

Explanation:

Answer 2

Answer:

Explanation:

With the information supplied, there is no answer to this question because you do not know the number of moles of sulfuric acid that you are trying to neutralize. To know this you would need to know the concentration of the sulfuric acid unless you really mean 8 mL of 100% pure sulfuric acid and, in this case, you would need to know the density. The density of 100% concentrated sulfuric acid can be looked up and is 1.8391 g/mL. So, with 0.8 mL you would have

0.8 mL * 1.8391 g/mL = 1.471 g

Now, convert this to moles

1.471 g / 98 g/mol H2SO4 = 0.0150 moles

The neutralization reaction is

2NaHCO3 + H2SO4 → Na2SO4 + 2H2CO3

2H2CO3 → 2H2O + 2CO2

Overall, the reaction is

2NaHCO3 + H2SO4 → Na2SO4 + 2H2O + 2CO2

The stoichiometry says you need two moles of NaHCO3 for every mole of sulfuric acid. So, you will need

0.0150 mole H2SO4 * 2 NaHCO3/1H2SO4 = 0.03 mole NaHCO3