Question

How many moles of sodium bicarbonate are needed to neutralise 0.8 ml of sulphuric acid at stp

Answer 1

This your question is rather inadequate and hence there is no answer to this question since you have not provided the number of moles of sulphuric acid.

The answer may be obtained only if you assume 0.8 ml is 100% and hence you will need to use the density which is 1. 8391 g/mL

Then to get the mass 0.8 x 1. 8391 = 1.471 g

Then the number of moles= 1.471 g / 98 g/mol H2SO4 = 0.0150 moles

2NaHCO3 + H2SO4 → Na2SO4 + 2H2O + 2CO2

This implies ratio of 2:1

and hence moles require to neutralize sulphuric acid is

2 x 0.015= 0.03 moles