Question

How many moles of sodium chloride are present in 300 cm3 of 2.0 M solution?​

Answer 1

Answer:

Here's your answer

Explanation:

The important distinction here is that 1 cm^3 is equal to 1mL. So we first convert to L;

250cm^3=250mL

250mL x ( 1L/1000mL) = .25L

Now, Molarity=Mole/L,

so we can rearrange the equation to find that

Molarity x L = mole

0.5 x .25 = 0.125 moles

Now that we have amount of moles, use your periodic table to find the molecular weight of Na and Cl and add those values together to get molecular weight of NaCl.

Na= 22.98 g/mol Cl = 35.45 g/mol

NaCl=58.44 g/mol

Lastly multiply the molecular weight by the amount of moles to find the amount of grams of NaCl.

58.44g/mol x 0.125moles= 7.31 g NaCl

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