Question

How many moles of sodium chloride are produced from 25.7 g of chlorine?

Answer 1

To find:

Moles of NaCl that can be produced from 25.7 gram of Chlorine.

Calculation:

First of all , we always get chlorine as Chlorine gas (diatomic) in nature.

$Cl_{2}\rightarrow 2Cl^{-}$

Moles of chlorine gas available = (25.7)/(71) = 0.36 moles.

$1 \: mole \: of \: Chlorine \: gas \: gives \: 2 \: moles \: of \: Chloride$

$\implies 0.36 \: mole \: of \: Chlorine \: gas \: gives \: (2 \times 0.36) = 0.72 \: moles$

Now, formation of NaCl :

$Na^{+}+Cl^{-}\rightarrow NaCl$

Considering Cl- (Chloride) to be limiting reagent:

$1 \: mole \: Cl^{-} \: gives \: 1 \: mole \: NaCl$

$\implies 0.72\: mole \: Cl^{-} \: gives \: ( 1 \times 0.72) = 0.72\: mole \: NaCl$

So, moles of NaCl produced is 0.72 moles.