How many moles of sodium chloride present in 250 mL of a 0.50 M NaCl solution?
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♤ Given:
● V = Volume = 250 ml = 0.25 L
● M = Concentration = 0.5M = molarity
● n = Number of moles ???
◇ Molarity is the concentration of solution contains certain number of moles in certain volume
☆ M= n ÷ v
So, n = M×V
☆ n = 0.5× 0.25 = 0.125 mole
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