How many moles of sodium ions are present in na^2so^4?
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Use the number of moles of sodium per mole of sodium sulfate.
Explanation:
Sodium sulfate is #Na_2##SO_4#
First, calculate the moles of sodium sulfate you have in a 14.2g sample.
Find the molar mass of sodium sulfate
molar mass = atomic mass in grams
2(23) + 32 + 4(16) = 142 grams per moleDivide the mass of the sample by the molar mass to obtain moles
#(14.2g)/(142gmol^-1)# = 0.1 mol
Now, for every 1 mol of #Na_2##SO_4# you have 2 moles of #Na^+# ions. Multiple the moles of #Na_2##SO_4# that you found just then by 2 to obtain the moles of sodium ions.
Use Avogadro's number (6.022 x #10^23#) to find the number of ions present. (Recall that Avogrado's number is the number of particles per mole of a substance).
6.022 x #10^23# x 0.2 mol = 1.2044 x #10^23#ions
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Use the number of moles of sodium per mole of sodium sulfate.
Explanation:
Sodium sulfate is #Na_2##SO_4#
First, calculate the moles of sodium sulfate you have in a 14.2g sample.
Find the molar mass of sodium sulfate
molar mass = atomic mass in grams
2(23) + 32 + 4(16) = 142 grams per moleDivide the mass of the sample by the molar mass to obtain moles
#(14.2g)/(142gmol^-1)# = 0.1 mol
Now, for every 1 mol of #Na_2##SO_4# you have 2 moles of #Na^+# ions. Multiple the moles of #Na_2##SO_4# that you found just then by 2 to obtain the moles of sodium ions.
Use Avogadro's number (6.022 x #10^23#) to find the number of ions present. (Recall that Avogrado's number is the number of particles per mole of a substance).
6.022 x #10^23# x 0.2 mol = 1.2044 x #10^23#ions
HOPE U LIKE !!
》》 BE BRAINLY 《《
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