Question

How many moles of solute are required in 300 gm solvent to prepare 3 molal solution

Answer 1

Answer:

Number of moles of the solute per kilogram of the solvent is molality.

Molality =

Mass of solvent (in kg)

Number of moles of the solute

Molarity =

Volume of solution (in L)

Number of moles of the solute

Mole fraction =

Number of moles of the solute + Number of moles of the solvent

Number of moles of the solute

Molar mass =

Number of moles of substance

Mass of substance