how many moles of solute will be present in 100gm of 5m solution?
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The number of moles of solute present in 1000 gm (or 1 kg) of solvent is known as molality.
Molality = Mass of solvent (in kg) Number of moles of solute
Molarity = volume of solution (in L) Number of moles of solute
Normality = volume of solution (in L) Number of gram equivalents of solute
Mole fraction = Number of moles of solute + Number of moles of solvent Number of moles of solute
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Answer:
20Gm/m
Explanation:
moles of solute = gm/m
= 100/5
Total Mole In the Solution = 20gm/m.
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