How many moles of sucrose should be dissolved in 500 g of water so as to get?
sagar9629:
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Let the molality of the solution be m. Then
∆Tf = Kf*m , and ∆Tb = Kb*m
∆Tf+∆Tb =(Kf+kB)*m = (1.86+0.51)*m = 2.37*m
Now, ∆Tf+∆Tb = 105 - 100 =5 = 2.37*m
Hence, m=5/2.37 = 2.11
Hence 2.11*100/1000= 0.211 mol of sucrose must be dissolved in 100 g of water.
Rquired mass of sucrose = 0.211 mol*342g/mol =72.2 g
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∆Tf = Kf*m , and ∆Tb = Kb*m
∆Tf+∆Tb =(Kf+kB)*m = (1.86+0.51)*m = 2.37*m
Now, ∆Tf+∆Tb = 105 - 100 =5 = 2.37*m
Hence, m=5/2.37 = 2.11
Hence 2.11*100/1000= 0.211 mol of sucrose must be dissolved in 100 g of water.
Rquired mass of sucrose = 0.211 mol*342g/mol =72.2 g
765 Views
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