Question

How many moles of water will be formed by processing between 10 grams of hydrogen (H2) and 64 grams of oxygen (O2)?

Answer 1

Answer:

2H2+O2→2H2O

10 g of hydrogen (molar mass 2 g/mol) = 2 g/mol  10 g = 5 mol 

 64 of oxygen  (molar mass 32 g/mol) = 32 g/mol  64 g = 2 mol 

As per the balanced chemical equation, 1 mole of oxygen will react with 2 moles of hydrogen to form 2 moles of water.

2 moles of oxygen will react with 2×2=4 moles of hydrogen to form 4 moles of water.

Here, oxygen is the limiting reagent and hydrogen is the excess reagent.