How many moles per litre of pcl5 has to be taken to obtain 0.1 mole of cl2 if the value of the equilibrium constant is 0.04?
Answers
Answered by
28
Hii dear,
# Answer- 0.25 moles
# Explaination-
Consider a as initial concentration of PCl5 and x be degree of dissociation.
Dissociation of PCl5 takes place according to following reaction
PCl5 → PCl3+Cl2
Initial conc: a 0 0
Final conc : a(1-x) ax ax
[Cl2] = 0.1 = ax ...(1)
Kc = ([PCl3][Cl2])/ [PCl5]
0.04 = (ax. ax)/a(1-x)
Solving this we'll get,
x=0.4
From (i)
a = 0.1/0.4 = 0.25
Hence, we can say moles of PCl5 added is 0.25 moles.
Hope that cleared your doubt...
# Answer- 0.25 moles
# Explaination-
Consider a as initial concentration of PCl5 and x be degree of dissociation.
Dissociation of PCl5 takes place according to following reaction
PCl5 → PCl3+Cl2
Initial conc: a 0 0
Final conc : a(1-x) ax ax
[Cl2] = 0.1 = ax ...(1)
Kc = ([PCl3][Cl2])/ [PCl5]
0.04 = (ax. ax)/a(1-x)
Solving this we'll get,
x=0.4
From (i)
a = 0.1/0.4 = 0.25
Hence, we can say moles of PCl5 added is 0.25 moles.
Hope that cleared your doubt...
Answered by
26
Answer:0.35
Explanation:
I hope this will definitely help u
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