Question

How many moles present in 54 gm of glucose?

Answer 1

the answer is 180.15588

Answer 2

The molar mass of glucose can be calculated from the molar masses of individual atoms present in it. From the molecular formula, C6H12O6, one can find there are 6 carbon atoms, 12 hydrogen atoms and 6 oxygen atoms in one molecule of glucose. 

Molar mass of C = 12 g mol-1

Molar mass of H = 1 g mol-1 

Molar mass of O = 12 g mol-1 

There fore,

Molar mass of C6H12O6=(6x12) + (12x1) + (6x16) = 72 + 12 + 96 = 180 g mol-1

So,moles present in 54 gm of glucose...

$\frac{54 \: gm}{180 \: gm. {mol}^{ - 1} }$
$= 0.3 \: mol$

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