Question

How many moles represented by 49g of sulphuric acid

Answer 1

Answer:

1 mole = 6.022×10^23

49g=?

=49×6.022×10^23

Answer 2

$moles=\frac{mass}{Mr}$

Mr of sulphuric acid is 98.079, mass of sulphuric acid has already been provided in the question: 49g

$moles=\frac{49}{98.079}$

$moles=0.4995$

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