How many mols of H is required to produce to 10moles of N/h³
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Answer:
Haber's process
N
2
(g)+3H
2
(g)⇌2NH
3
(g)
10 moles needs to be produced
2 moles NH
3
→3 moles of H
2
Hence 10 moles of NH
3
→
3×10/2
=15 of moles of H
2
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