How many multiple of 4 lie between 10 and 250? also their sum
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AP= 12,16,20.....,248
An= 248
A+(n-1)d=248
12+(n-1)4=248
12+4n+4=248
4n=248-16
n=232/4
n=58
58 multiple lie between 10 to 250
Sn=n/2 (2a+(n-1)d)=58/2(2×12+(58-1)4)
=29(24+57×4) =29(24+228)
=29×252 =6958
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