Question

How many multiples of 18 lie between 50 and 100

Answer 1

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Answer:-

first three multiples of 18 after 50 = 54,72,........

last multiple of 18 before 100 = 90

So,

a = 54

d = 72-54 = 18

an = 100

an = a+(n-1)d

100 = 54+(n-1)18

46 = 18n-18

46+18 = 18n

64 = 18n

n = 64/18

n = 32/9