Question

how many multiples of 4 are there between 10 and 250.


Arithmatic progression.​

Answer 1

Answer:We will use the AP:

AP= 12, 16, 20,......248

first term, a=12,

common difference, d=14

last term ,an= 248

an = a + (n-1) d

248 = 12 + (n-1)4

n - 1 = 236/4

n = 59 + 1 = 60

Sn = (n/2) + (a + an) = (60/2) + (12+248) = 7800

hence there are 60 multiples of 4 between 10 and 250. Their sum is 7800.

Step-by-step explanation: