Question

how many multiples of 4 are there between 8 and 252​

Answer 1

Answer:

Answer:We will use the AP:

Answer:We will use the AP:AP= 12, 16, 20,......248

Answer:We will use the AP:AP= 12, 16, 20,......248first term, a=12,

Answer:We will use the AP:AP= 12, 16, 20,......248first term, a=12,common difference, d=14

Answer:We will use the AP:AP= 12, 16, 20,......248first term, a=12,common difference, d=14last term ,an= 248

Answer:We will use the AP:AP= 12, 16, 20,......248first term, a=12,common difference, d=14last term ,an= 248an = a + (n-1) d

Answer:We will use the AP:AP= 12, 16, 20,......248first term, a=12,common difference, d=14last term ,an= 248an = a + (n-1) d248 = 12 + (n-1)4

Answer:We will use the AP:AP= 12, 16, 20,......248first term, a=12,common difference, d=14last term ,an= 248an = a + (n-1) d248 = 12 + (n-1)4n - 1 = 236/4

Answer:We will use the AP:AP= 12, 16, 20,......248first term, a=12,common difference, d=14last term ,an= 248an = a + (n-1) d248 = 12 + (n-1)4n - 1 = 236/4n = 59 + 1 = 60

Answer:We will use the AP:AP= 12, 16, 20,......248first term, a=12,common difference, d=14last term ,an= 248an = a + (n-1) d248 = 12 + (n-1)4n - 1 = 236/4n = 59 + 1 = 60Sn = (n/2) + (a + an) = (60/2) + (12+248) = 7800

Answer:We will use the AP:AP= 12, 16, 20,......248first term, a=12,common difference, d=14last term ,an= 248an = a + (n-1) d248 = 12 + (n-1)4n - 1 = 236/4n = 59 + 1 = 60Sn = (n/2) + (a + an) = (60/2) + (12+248) = 7800hence there are 60 multiples of 4 between 10 and 250. Their sum is 7800.

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Answer 2

Answer:

the no of multiple

s of 4 between 8 and 252 ar