Question

how many multiples of 4 lie between 10 and 250

Answer 1

first multiple is 12 and last is 240
according to the formula
To get the position of last term I.e., 240
An = a + (n - 1)d
240 = 12 + (n - 1)4
240 = 12 + 4n -4
240 = 8 + 4n
240 - 8 = 4n
232/4 = n
58 = n
So, the position of last number I.e., 240 of an A.P. is 58

Answer 2

Answer:

Step-by-step explanation:

As we know 1st multiple is 12 and last multiple is 248.

so,

a=12,  

an=248 ,

d=4

we know, an=a+(n-1)d

                    248=12=(n-1)4

                    248=12+ 4n-4

                    248=8+4n

                     4n=248-8

                     4n=240

                     n=$\frac{240}{4}$

                     n=60

so there are 60 multiples of 4 between 10 and 250.