How many multiples of 9 can be found which are less than 9999 and perfect cube root??
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Answered by
1
Answer:
7
Step-by-step explanation:
- only perfect cubes that are multiples of 9 can be the those whose cube roots are multiples of 3
- 3*3*3=27
- for every multiple of 3 it will atleast have 27
- 6*6*6=(3*3*3)*(2*2*2)
- The numbers are 27,216,729,1728,3375,5832,9261
Answered by
0
Answer:
Step-by-step explanation:
Yes
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