How many multiples of 9 lies between 700 to 800
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Answer:
Here series will be = 306, 315, 324, 333, ........693
so we have the first term a = 306 and d = 9 and last term l = 693
693 =306 + (n-1)
77 = 34 + (n-1)
n = 77 - 34 + 1
= 44
sum = n/2 a + l
=44/2(306+693)
=22(999)
=21978
Step-by-step explanation:
I hope this is correct answer
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