Question

how many multiplus of a 3 lie between 14 and 310​

Answer 1

Answer:

15, 18,21,......309

Tn= a+(n-1)d

309= 15+(n-1)3

309=15+3n-3

309=12+3n

309-12=3n

297=3n

n=297/3

n=99

so, between 14 to 310

there are 99 number which is divisible by 3

Answer 2

Answer:

All multiples of 3 b/w 14 and 310 forms AP

Step-by-step explanation:

where

a=15

a218

an=309

d=3

n=?

Since, an=a+(n-1)d

309= 15 +(n-1)3

= 15+3n-3

=12+3n

3n=309-12

n=297÷3

n=99

therefore 99 multiples of 3 lie b/w 14 and 310