Question

How many n2 molecules are present in 1.12 ltr of 80?

Answer 1

2.24 ltr is total volume of n2 gas(28u) right

and we are given about 1.12 ltr of n2 gas (28u)

thus on comparing both of these case we will get

$2.24 \div 28\div 1.12 \div 28 \\ here \: 28 \: and \: 28 \: will \: get \: cancelized \: then \: we \: will \\ 2.24 \div 1.12 = 1 \div 2 = 0.5$

thus we get 0.5 molecules of n2 gas