Question

How many NaBr molecules are contained in
25 g of NaBr? (Atomic mass of Na = 23, Br =
35)
2.34 x 1020 molecules
102.96 molecules
0.24 molecules
2.59 x1023 molecules
|​

Answer 1

Answer:

1.463 x 10^23 molecules

Explanation:

Answer 2

Answer:

There are 2.59 x10^23 molecules contained in 25 g of NaBR

Explanation:

To calculate the number of molecules in 25 g of NaBr, we need to first determine the molar mass of NaBr and then use Avogadro's number to convert from mass to number of molecules.

The molar mass of NaBr is calculated as follows:

Molar mass of NaBr = atomic mass of Na + atomic mass of Br

= 23 + 35

= 58 g/mol

Next, we can use Avogadro's number, which is the number of atoms or molecules in one mole of a substance, to convert from mass to number of molecules:

Avogadro's number = 6.022 x 10^23 molecules/mol

Number of NaBr molecules = (25 g) / (58 g/mol) x (6.022 x 10^23 molecules/mol)

= 2.59 x 10^23 molecules

Therefore, there are 2.59 x 10^23 NaBr molecules contained in 25 g of NaBr.

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